Casey's Colossal Algebra
Problems
By: Casey S

Linear Equation
Linear
Equations are equations that when solved; one variable equals 1 number.
| 1. 4K-(2+K)=10+2K | 1. Original problem. |
| 2. 4K-2-K=10+2K | 2. Distrubute the -1 to the (2+K) |
| 3. 3K-2=10+2K | 3. Combine like terms (4K and -K). |
| 4. K-2=10 | 4. All the variables need to be on one side, so subtract 2K from both sides. |
| 5. K=12 | 5. Finally, add 2 to both
sides to find your answer.
ITS EASY AS THAT! |

Literal Equation
Literal
Equations have more than one variable. They are solved for a specific
variable. A numerical answer is not available for this type of equation.
| 1. P=2L+2W | 1. Original problem. |
| 2. P=2L+2W | 2. Solve for W. |
| 3. P-2L=2W | 3. Subtract 2L from each side of the equation. |
| 4. P-2L/2=W | 4. Divide each side of the equation by 2. Thats your answer. |

Writing the equation of a line.
Write the equation of a line
in slope intercept form with slope = 4 through the point (4,7).
| 1. y=mx+b | 1. Original equation. |
| 2. 7=3(4)+b | 2. Substitute in the points for y and x. |
| 3. 7=12+b | 3. Multiply to simplify the problem. |
| 4. -5=b | 4. To find b subtract 12 from both sides. |
| 5. y=4x-5 | 5. Re-write the problem in slope-intercept form and you'are finshed. Simple as that! |
Using Point Slope Form
| 1. y-y1=m(x-x1) | 1. Original equation. |
| 2. y-7=4(x-4) | 2. Substitute in the points for y and x. |
| 3. y-7=4x-16 | 3. Multiply to simplify the problem. |
| 4. y=4x-9 | 4. Add 7 to both sides. There you have it now your back to slope intercept form. Easy as That. |
Using Standard Form
| 1. y=4x-9 | 1. Original problem. Convert to standard form. |
| 2. -4x+y=-9 | 2. Put the x on the left side to put in standard form. |
| 3. 4x-y=9 | 3. Multiply the equation by a -1 to make the x postive. IT IS EASY AS THAT NOW U KNOW HOW TO WORK EQUATIONS. |
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