|
Visual Basic (VB and VBA) |
|
Copyright 1999-2001 Christopher Greaves. All rights reserved. Home Page and email to [email protected] |
| If in doubt, record a macro and inspect the entrails! |
Please read the DISCLAIMER.
Here is an INDEX to all the procedures.
You will probably need one copy of my GLOBAL DECLARATIONS.
Public Function szStripLineOfComments(ByVal szLine As String) As String
Dim iCounter As Integer
Dim vaSingleQuotePositions As Variant
''' Get an array of all the positions of Chr$(39)
vaSingleQuotePositions = vaGetOccurencesOfStringInString(szLine, Chr$(39))
''' If is Null, then goto EndFunction
If Not IsNull(vaSingleQuotePositions) Then
''' The assumption in VBA is,if there is a single quote, it MUST be wrapped
''' within double quotes (assuming no line continuations), else is demarkating the start of a comment
''' The first ' without a " to the right of it in the string is a comment.
For iCounter = LBound(vaSingleQuotePositions) To UBound(vaSingleQuotePositions)
If Not CBool(InStr(1, Right$(szLine, Len(szLine) - CLng(vaSingleQuotePositions(iCounter))), Chr$(34))) Then
szLine = Trim$(Left$(szLine, CLng(vaSingleQuotePositions(iCounter)) - 1))
Exit For
End If
Next iCounter
End If
szStripLineOfComments = szLine
End Function
| We all knew nothing when we started … |
|
Home Page and Contact Information Send email to [email protected]. This page was last updated Thursday, November 15, 2001 |