College Algebra
Tutorial
10: Adding and Subtracting Rational
Expressions
Learning
Objectives |
After completing this tutorial, you should be able to:
- Find the least common denominator of rational expressions.
- Add and subtract rational expressions.
|
Introduction |
| Do you ever feel dazed and confused when working with
fractions? If so, you are not alone. This is your
lucky day! We have a whole other tutorial devoted to rational
expressions (fractions). In this tutorial we will be looking
at adding and subtracting them. If you need a review on
simplifying rational expressions, feel free to go back to Tutorial
8: Simplifying Rational Expressions. It is time to get
started with this tutorial. |
Tutorial |
Adding or Subtracting Rational
Expressions with Common Denominators

|
|
Why do we have to have a common denominator
when we add or subtract rational
expressions????? |
| Good question. The denominator indicates what type of
fraction that you have and the numerator is counting up how many of
that type you have. You can only directly combine fractions
that are of the same type (have the same denominator). For
example if 2 was my denominator, I would be counting up how many
halves I had. If 3 was my denominator, I would be counting up
how many thirds I had. But I would not be able to add a
fraction with a denominator of 2 directly with a fraction that had a
denominator of 3 because they are not the same type of
fraction. I would have to find a common denominator first,
which we will cover after the next two
examples. |
Example 1: Add . |
| Since the two denominators are the same, we can go right into
adding these two rational
expressions. |
| Step 1: Combine the
numerators together
AND
Step 2: Put the sum
or difference found in step 1 over the common
denominator. |
 |
*Common denominator of 5x - 2
*Combine the numerators
*Write over common denominator
*Excluded values of the original
den. |
| Step 3: Reduce
to lowest terms. |
| Note that neither the numerator nor the denominator will
factor. The rational expression is as simplified as it gets.
Also note that the value that would be excluded from the
domain is 2/5. This is the value that makes the
original denominator equal to
0. |
Example 2:
Subtract . |
| Since the two denominators are the same, we can go right into
subtracting these two rational
expressions. |
| Step 1: Combine the
numerators together
AND
Step 2: Put the sum
or difference found in step 1 over the common
denominator. |
 |
*Common denominator of y - 1
*Combine the numerators
*Write over common denominator
|
| Step 3: Reduce
to lowest terms. |
 |
*Factor the num.
*Simplify
by div. out the common factor of (y -
1)
*Excluded values of the original
den. |
| Note that the value that would be excluded from the domain is
1. This is the value that makes the original
denominator equal to 0. |
|
Least Common Denominator
(LCD) |
Step 1: Factor all
the denominators
Step 2: The LCD is
the list of all the DIFFERENT factors in the denominators raised to
the highest power that there is of each
factor. |
Adding and Subtracting Rational
Expressions Without a Common
Denominator |
| Step 2: Write
equivalent fractions using the LCD if
needed. |
| If we multiply the numerator and denominator by the exact same
expression it is the same as multiplying it by the number 1.
If that is the case, we will have equivalent expressions when
we do this.
Now the question is WHAT do we multiply top and bottom by to
get what we want? We need to have the LCD, so you look to
see what factor(s) are missing from the original denominator that is
in the LCD. If there are any missing factors then that is what
you need to multiply the numerator AND denominator
by. |
Example 3: Add . |
| The first denominator has the following two
factors: |
 |
*Factor the GCF |
| The second denominator has the following
factor: |
| Putting all the different factors together and using the
highest exponent, we get the following
LCD: |
| Since the first rational expression already has the LCD,
we do not need to change this
fraction. |
 |
*Rewriting denominator in factored
form
|
| Rewriting the second expression with the
LCD: |
 |
*Missing the factor of (y - 4) in the den.
*Mult. top and bottom by (y - 4)
|
 |
*Combine the numerators
*Write over common denominator
|
| Step 4: Reduce
to lowest
terms. |
 |
*Simplify
by div. out the common factor of y
*Excluded values of the original
den. |
| Note that the values that would be excluded from the domain
are 0 and 4. These are the values that make the
original denominator equal to
0. |
Example 4: Add . |
| The first denominator has the following
factor: |
| The second denominator has the following two
factors: |
| Putting all the different factors together and using the
highest exponent, we get the following
LCD: |
| Rewriting the first expression with the
LCD: |
 |
*Missing the factor of (x
+ 1) in the den. *Mult. top and bottom by (x
+ 1)
|
| Since the second rational expression already has the LCD,
we do not need to change this
fraction. |
 |
*Rewriting denominator in factored
form
|
 |
*Combine the numerators
*Write over common denominator
*Excluded values of the original
den. |
| Step 4: Reduce
to lowest
terms. |
| This rational expression cannot be simplified down any
farther. |
| Also note that the values that would be excluded from the
domain are -1 and 1. These are the values that make the
original denominator equal to
0. |
Example 5:
Subtract . |
| The first denominator has the following two
factors: |
| The second denominator has the following two
factors: |
| Putting all the different factors together and using the
highest exponent, we get the following
LCD: |
| Rewriting the first expression with the
LCD: |
 |
*Missing the factor of (x
- 8) in the den. *Mult. top and bottom by (x -
8)
|
| Rewriting the second expression with the
LCD: |
 |
*Missing the factor of (x
+ 5) in the den. *Mult. top and bottom by (x +
5)
|
 |
*Combine the numerators
*Write over common denominator
*Distribute the minus sign through the
( )
|
| Step 4: Reduce
to lowest
terms. |
 |
*Factor the num.
*No common factors to divide
out
*Excluded values of the original
den. |
| Note that the values that would be excluded from the domain
are -5, -1 and 8. These are the values that make
the original denominator equal to
0. |
Practice
Problems |
| These are practice problems to help bring you to the next
level. It will allow you to check and see if you have an
understanding of these types of problems. Math works just like anything else, if you want to get
good at it, then you need to practice it. Even the best
athletes and musicians had help along the way and lots of practice,
practice, practice, to get good at their sport or
instrument. In fact there is no such thing as too
much practice.
To get the most out of these, you should work the problem out
on your own and then check your answer by clicking on the link for
the answer/discussion for that problem. At the link
you will find the answer as well as any steps that went into finding
that answer. |
Practice Problems 1a - 1b:
Perform the indicated
operation. |
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These
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All contents copyright (C) 2002, WTAMU and Kim Peppard.
All rights reserved. Last revised on June 25,
2002 by Kim Peppard. |