Form 5 Chemistry Quiz 3
Chapter 21: Sulphuric acid and Sulphur
dioxide
Marking Scheme

The red vapour formed by burning sulphur in the
test tube was mixed with oxygen and ignited at the jet. Gaseous product G was
produced in burning.
(a) Name
the gaseous product G. [1]
Sulphur dioxide 1
(b) Write an equation for the formation of G. [1]
S(s) + O2(g) ¾® SO2(g) 1
(c) Gas G was then sucked into and
dissolved in the test tube containing water to form solution Z. Name the
solution Z. [1]
Sulphurous acid / sulphur
dioxide solution / aqueous sulphur dioxide 1
(d) What will be observed if solution Z is
added into the following solution separately? Explain your answer with the help
of an ionic equation.
(i) Bromine water. [2]
Brown
bromine water decolorized. 1
(Turn
brown to colourless)
Br2 + SO32-
+ H2O ¾® 2Br- + SO42-
+ 2H+ 1
OR Br2 +
SO2 + 2H2O ¾® 2Br- + SO42-
+ 4H+ (1)
(ii) Acidified potassium
permanganate solution. [2]
Purple
acidified potassium permanganate solution decolorized. 1
(Turn
purple to colourless)
2MnO4- + 5SO32-
+ 6H+¾® 2Mn2+ + 5SO42-
+ 3H2O 1
OR 2MnO4-
+ 5SO2 + 2H2O ¾® 2Mn2+ + 5SO42-
+ 4H+ (1)
(iii) Acidified potassium dichromate
solution. [2]
Orange
acidified potassium dichromate solution turn green. 1
(Turn
Orange to green)
3SO2
+ Cr2O72- + 2H+ ¾® 3SO42- +
2Cr3+ + H2O 1
OR 3SO32- + Cr2O72-
+ 8H+ ¾® 3SO42- +
2Cr3+ + 4H2O (1)
(e) A red flower is put into solution
Z.
(i) What would you observe? [1]
Red colouration fade out /
decolorized / turn pale red / turn white 1
(ii) Write an equation to show the
reaction. [1]
SO32- +
dye ¾® SO42- + (dye – O) 1
(iii) What is the function of the
solution Z in the reaction? Why? [2]
Sulphur
dioxide reduce dye molecule / remove O from dye molecule 1
(f) What would you observe when
acidified barium nitrate solution is added in the resulting solution of (e)(i).
Explain your answer with the help of an ionic equation. [2]
White / red precipitate formed 1
Ba2+(aq) + SO42-(aq)
¾® BaSO4(s) 1