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for your reference only!
The "best" answers are based on
your actual experimental results!
3. Blue.
5. The paper changed from orange to
green (then white).
6. It changes to red then white.
1. The colour on the petals fades.
The
petals become colourless.
A
white precipitate is formed.
Sulphate
ion. Aqueous sulphur dioxide / sulphite solution is oxidized to sulphate ion.
2. The colour becomes red then fades.
The
pH paper becomes colourless.
A
white precipitate is formed.
Sulphate
ion. Aqueous sulphur dioxide / sulphite solution is oxidized to sulphate ion.
3. SO2(g) + H2O(l)
¾®
H2SO3(aq)
H2SO3(aq)
D
2H+(aq) + SO32-(aq)
4. SO32-(aq) +
dye with O ¾®
SO42-(aq) + dye without O
1. Orange.
Colourless.
Bromine
is reduced to bromide which is colourless.
2Br-(aq)
¾®
Br2(g) + 2e-
2. Orange.
Green.
The
orange dichromate ion is reduced to chromium(III) ion which is green.
14H+(aq)
+ Cr2O72-(aq) + 6e- ¾®
2Cr3+(aq) + 7H2O(l)