"Gypsy & Girl with mirror" - Set of Ambiguous Figures
G. H. Fisher, Materials for experimental studies of ambiguous and embedded figures, Res. Bull. No. 4, 1996, Dept. of Psychol., University of Newcastle upon Tyne.

NOTE: The documentation of this experiment is NOT complete!
Last edited: 14-09-1999


I conducted an experiment with three other people (Robert Morrison, Matthew Cocker and James Castleman) to investigate if there are effects of prior exposure of one of the aspects before an ambiguous figure was shown on the probability that both aspects are have equal chances of being seen..

The hypothesis was: The participants exposed to one of the aspects prior to the ambiguous figure will be more likely to see this aspect in the ambiguous figure.

The participants were students in the 10th year level of a school offering secondary education in Melbourne, Australia.

There were 83 participants in total. However, 7 protocols had to be discarded because the participants failed to make a distintion between the two different aspects in the ambiguous figure.

NUMBER OF OCCASIONS UPON WHICH THE FIRST SHOWN ASPECT
OF THE AMBIGUOUS FIGURE WAS SEEN UPON EXPOSURE.
Image1234567 89101112131415
Class A17171615151514 1312974332
Class B23232323232221 1919171512554
Class C20202020202020 1919171712775
Class D16161616161616 1615131211888
Sum of Classes76767574747371 6765565139232319


NUMBER OF OCCASIONS UPON WHICH THE SHOWN ASPECT OF
THE AMBIGUOUS FIGURE WAS (IN-)CORRECTLY IDENTIFIED.
Image1234567 89101112131415
correctly identified767675747473 716711202537535357
incorrectly identified0012235 965565139232319



Mean and Variance for Binomial Distribution

Mean = N * p
Variance = N * p * q
Standard Deviation = (N * p * q) ^ ½
where N is the total number of participants
p is the probability to see the first aspect
q is the probability to see the second aspect


In this experiment, the values for the variables are:

N = 83, p = 0.5, q = 0.5

Mean = 83 * 0.5 = 41.5
Variance = 83 * 0.5 * 0.5 = 20.75
Standard Deviation = (83 * 0.5 * 0.5) ^ ½ = (20.75) ^ ½ = 4.56


Therefore to encorporate 95.44% of the participants, if they behave according to a Normal Distribution we substract and add two standard deviations to the calculated mean.
Thus the range of the number of responses lies between 32.38 and 50.62 if the picture were shown by itself with no prior exposure to any of the aspects.

The results from the tables above show that the reponses indicating the number of occasions the first-named aspect was seen was 67.
This lies clearly above the range calculated by the methods involved with a Normal Distribution.
Thus we can say that the prior exposure of the images from 1 to 7 has caused the participant to be more likely to see the first-shown aspect in the ambiguous figure.


You may not reproduce this text or tables in any way unless you have permission to do so.
Copyright 1999 by Hayko Riemenschneider
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