Chapter 14
Strong Acids:
       HCl
       HBr
       HI
       HNO3
       H2SO4
       HClO4
Strong Bases:
*anything in groups 1&2 on the periodic table with OH-*
ex.
NaOH
Ca(OH)2
Mg(OH)2
%ionization or dissaociation = Amount Disassociated / initial concentration  X 100

pH = -log [H+]              Kw= 1x10^-14               [H+] [OH-] = 1x10^-14

Acid > 1x10^-7              Base < 1x10^-7                     Kb- OH           Ka- H


pOH = -log [M]               pH = -log [M]
Highest to Lowest pH:

RbOH        H2S            CaCl2            NaCN            HI


NH3= 1.8x10^-15  Kb
Example:

A 0.1 M solution of HC3H5O2 has a pH of 1.35.
What is the Ka?

       HC3H5O2  --->   C3H5O2-  +  H+
I        .1                         0               0
C        -x                         x                x
E        .1-x                        x             x

       [H+] = 10^-1.35 = 4.47x10^-2 M


   (4.47x10^-2)^2
----------------------  =
   .1- (4.47x10^-2)

              Ka=  .0361
Main Page
Hosted by www.Geocities.ws

1