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Lab 5 of 2LB
Lab 8 of 40B
Specific Heat of Metals

Courtesy of Yeuh-feng Chiang

1. Latent Heat of Liquid Nitrogen

  • Room Temperature, Troom = 298K
  • Temperature of liquid nitrogen, TN2 = 77K
  • 1 (Joul) = 0.239 (Cal)
  • The measured voltage and current are:

  • V = ______, Unit:(        )

  • I = ________, Unit:(       )

  • P = I V =__________ Watt =___________( cal/sec)

  • Time (sec)

    Mass (g)

    Time (sec)

    Mass (g)

    -30

     

    80

     

    -20

     

    90

     

    -10

     

    100

     

    0

     

    110

     

    10

     

    120

     

    20

     

    130

     

    30

     

    140

     

    40

     

    150

     

    50

     

    160

     

    60

     

    170

     

    70

         
  • D M = _____, Unit:(        )

  • D t = ______, Unit:(        )

  • L = ( PD t )/D M = _______, Unit:(        )

  • Compare the calculated value of L with "standard " value of 47.8 cal/g

  • 2. Specific heat of Metals

    Massmetal, (g)

    MassAluminum=

    MassCopper=

    MassLead=


    Time (sec)

    MassN2 (g)
    for C Aluminum

    MassN2 (g)
    for C Copper

    MassN2 (g)
    for C Lead

    Time (sec)

    MassN2 (g)
    for C Aluminum

    MassN2 (g)
    for C Copper

    MassN2 (g)
    for C Lead

    -60

         

    30

         

    -50

         

    40

         

    -40

         

    50

         

    -30

         

    60

         

    -20

         

    70

         

    -10

         

    80

         

    0

         

    90

         

    10

         

    100

         

    20

         

    110

         

    D T =(Troom-TN2) = _________, Unit:(        )

    cmetal = ( MN2L )/( MmetalD T )

    Record your final result in the following table:

    Massmetal
    (g)

    MassN2
    (g)

    c v= cmetal
    (cal/g-K)

    Atomic weight
    (g/mol)

    Experimental Molar Cv
    (cal/mol-K)

    %ERROR
    MAluminum=

     

    c Aluminum =

    26.98

      %
    Mcopper=

     

    ccopper =

    63.55

      %
    Mlead=

     

    c Lead =

    207.19

      %

    Question: How do the results compare with the theoretical value, 3R = 24.94 ( J/mol-K ) = 5.96 ( cal/mol-K )?

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