Lab 7, Inelastic Collisions03/19/2000

Courtesy of Chiung-Yuan Lin and Benli Young

I. Perfectly Inelastic Collisions

1. Prepare and weigh the gliders and all masses:

Object

Mass, Unit:( )

Glider with pin

 

Glider with plug

 

Masses

 

 

 

 

 

 

2. Set up timing photo-gates:

The length of Glider should be the total length which the photo-gate can detect.

Item

Glider with pin

Glider with plug

Average of two Gliders

Length, Unit:( )

 

 

 

3. Make measurements: (Just fill in the data)

  1. One glider initially at rest, the other started by the launcher
  2. The positive velocities are measured to the right

    You do all three cases and choose only one case to complete the whole row. Your sample calculation is not required here.

    m1

    (kg)

    m2

    (kg)

    V1i

    (m/s)

    V2i

    (m/s)

    Vf

    (m/s)

    Pi

    (kg-m/s)

    Pf

    (kg-m/s)

    D P

    (kg-m/s)

    Ki

    (Joul)

    Kf

    (Joul)

    D K

    (Joul)

    (DK / Ki)´ 100% (DK / Ki)´ 100%
                          % %
                          % %
                          % %

  3. Both gliders started by the launchers

You do all three cases, choose only one case to go through it to (D K / Ki )´ 100% and write down your sample calculation.

m1

(kg)

m2

(kg)

V1i

(m/s)

V2i

(m/s)

Vf

(m/s)

Pi

(kg-m/s)

Pf

(kg-m/s)

DP

(kg-m/s)

Ki

(Joul)

Kf

(Joul)

DK

(Joul)

(DK / Ki )´ 100%

 

 

 

 

 

 

 

 

 

   

%

 

 

 

 

 

 

 

 

 

 

 

%

 

 

 

 

 

 

 

 

 

 

 

%

 4. Answer the Additional Question I, (2 point)

Starting from the two equations on Page 43, derive an expression of DK only in terms of m1, m2, V1i, V2i. Then simplify your expression to prove that DK ³ 0 for any initial velocities. Your mathematical work stands one point. (0.5 points for your final answer) How can we make DK = 0? (0.5 points) Is it possible to perform the specific situation today? Why?

Hint: m1V1i+m2V2i = (m1+m2)Vf, (a + b)2 = a2 + 2ab + b2, and (a - b)2 = a2 - 2ab + b2

 

II. Other inelastic collisions

1. 

m

(kg)

Vi

(m/s)

Vf

(m/s)

Ki

(Joul)

Kf

(Joul)

DK

(Joul)

(DK/ Ki )x100%

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

2. Plot Graph "D K versus Ki".

3. Answer Question 2 on page 43: Is a constant fraction of energy lost, or is a fixed amount of energy lost?

Hint: Do not answer this question with a simple "YES" or "NO" or you loss 1 point. Use your Graph "DK versus Ki" to answer this question.

 

 

Samples of Part I. Perfectly Inelastic Collisions

Below is a sample when performing collisions with the “wax” glider initially at rest.

|v1i| = 0.638(m/sec), |v2i| = 0.000(m/sec), |vf| = 0.303(m/sec)

Special option values - "collision Timer" Mode

Row

velocity

velocity

#

(m/sec)

(m/sec)

1

0.6376

0.3025

2

Error

0.2972

 

Carefully read the following remark when performing collisions by launching both gliders.

Special option values - "collision Timer" Mode

Row

velocity

velocity

#

(m/sec)

(m/sec)

1

0.5470

0.3862

Below is a sample when vf goes back and forth.

|v1i| = 0.547(m/sec), |v2i| = 0.386(m/sec), |vf| = 0(m/sec)

 

 

 

Below is a sample when vf goes fast enough.

|v1i| = 0.391(m/sec), |v2i| = 0.468(m/sec), |vf| = 0.0938(m/sec)

Special option values - "collision Timer" Mode

Row

velocity

velocity

#

(m/sec)

(m/sec)

1

0.3909

0.4677

2

Error

0.09375

3

Error

0.09110

 

Below is a sample when vf goes too slow.

|v1i| = 0.549(m/sec), |v2i| = 0.468(m/sec), |vf| = 0.0148(m/sec)

Special option values - "collision Timer" Mode

Row

velocity

velocity

#

(m/sec)

(m/sec)

1

0.5489

0.4678

2

Error

0.01483

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