Chapter 3:
Section 3-3 Cramer's Rule
by Jamie D.
Suzie had a birthday party for her 12th birthday. She invited 10 boys (x) and 12 girls( y). There was a total of 22 people who came to her party. For her 13th birthday party, she invited 13 boys (x) and 15 girls (y). There was a total of 28 people at her party. The solution for this problem is:
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the solution to the system is: ax+by=e 10X + 12Y = 22 |
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cx+dy=f 13X + 15Y = 28 |
where:
[E B] [A E]
[F D] [C F] [A B]
X = _______, Y = ________, and [C D] cannot equal 0
[A B] [A B]
[C D] [C D]
[22 12] [10 22]
[28 15] [13 28]
x = _______, y = _______
[10 12] [10 12]
[13 15] [13 15]
Cross Multiply the matrices to the answer |
then it becomes: X = 22(15)-(22)(28)
10(15)-(12)(13)
= -286/-6
= 143/3
Y = 10(28)-(22)(13)
10(15)-(12)(13)
= -6/-6
= 1
So....the solution is (143/3, 1)
Need more help? Go to these webpages...
http://www.sparknotes.com/math/algebra2/.dir/
http://home.xnet.com/~fidler/triton/math/review/mat085/mat085.htm
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~Sophocles~
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| Algebra II | Jamie D. | Mrs. Blackwell's Page |
| Mrs. Blackwell | 03 - 06 - 03 |