\documentclass[10pt,a4paper,final]{article} %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% \usepackage{amsmath} \usepackage{graphicx} \usepackage[latin1]{inputenc} \setlength{\topmargin}{-0.75in} \setlength{\textheight}{12.25in} \setlength{\oddsidemargin}{0.0in} \setlength{\evensidemargin}{0.0in} \setlength{\textwidth}{6.5in} \def\labelenumi{\arabic{enumi}.} \def\theenumi{\arabic{enumi}} \def\labelenumii{(\alph{enumii})} \def\theenumii{\alph{enumii}} \def\p@enumii{\theenumi.} \def\labelenumiii{\arabic{enumiii}.} \def\theenumiii{\arabic{enumiii}} \def\p@enumiii{(\theenumi)(\theenumii)} \def\labelenumiv{\arabic{enumiv}.} \def\theenumiv{\arabic{enumiv}} \def\p@enumiv{\p@enumiii.\theenumiii} \pagestyle{plain} \setcounter{secnumdepth}{0} \newtheorem{theorem}{Theorem} \newtheorem{acknowledgement}[theorem]{Acknowledgement} \newtheorem{algorithm}[theorem]{Algorithm} \newtheorem{axiom}[theorem]{Axiom} \newtheorem{case}[theorem]{Case} \newtheorem{claim}[theorem]{Claim} \newtheorem{conclusion}[theorem]{Conclusion} \newtheorem{condition}[theorem]{Condition} \newtheorem{conjecture}[theorem]{Conjecture} \newtheorem{corollary}[theorem]{Corollary} \newtheorem{criterion}[theorem]{Criterion} \newtheorem{definition}[theorem]{Definition} \newtheorem{example}[theorem]{Example} \newtheorem{exercise}[theorem]{Exercício} \newtheorem{lemma}[theorem]{Lemma} \newtheorem{notation}[theorem]{Notation} \newtheorem{problem}[theorem]{Problem} \newtheorem{proposition}[theorem]{Proposition} \newtheorem{remark}[theorem]{Remark} \newtheorem{solution}[theorem]{Solution} \newtheorem{summary}[theorem]{Summary} \newenvironment{proof}[1][Proof]{\textbf{#1.} }{\ \rule{0.5em}{0.5em}} \begin{document} \begin{figure}[!htb] \centering \includegraphics[scale=0.4]{logoNH.ps} \end{figure} \vspace{2cm} \begin{exercise} Sendo $A=\left( \begin{array}{cc} 3 & -1 \\ 4 & 0 \\ \end{array} \right)$ e $B=\left( \begin{array}{cc} -1 & 7 \\ -2 & 4 \\ \end{array} \right)$, encontre o valor da matriz X, para que se tenha $\frac{X-A}{2}=\frac{X+2B}{3}$. \end{exercise} \vspace{2cm} \begin{exercise} Sendo $A$ uma matriz $3$ por $3$, definida pela lei $a_{ij}=\begin{cases} 1, & \text{se $i=j$},\\ i^2, & \text{se $i\neq j$}. \end{cases}$ Responda: \begin{description} \item[(a)] Determine a mattriz A; \item[(b)] Encontre o traço desta matriz; \item[(c)] Encontre o determinante desta matriz; \item[(d)] Encontre a inversa desta matriz, se existir. \end{description} \end{exercise} \vspace{2cm} \begin{exercise} Se $\left( \begin{array}{cc} 2 & 3 \\ 1 & 4 \\ \end{array} \right)$ $\left( \begin{array}{cc} a & 1 \\ -2 & b \\ \end{array} \right)$ = $\left( \begin{array}{cc} 5 & 7 \\ -5 & 9 \\ \end{array} \right)$, calcule o valor de $a+b$. \end{exercise} \vspace{2cm} \begin{exercise} Dadas as matrizes $A=\left( \begin{array}{cc} 2 & 0 \\ -1 & 3 \\ \end{array} \right)$ e $B=\left( \begin{array}{cc} 2 & \frac{1}{2} \\ 4 & 3 \\ \end{array} \right)$, encontre o valor de $-3BA$. \end{exercise} \vspace{1cm} \emph{"Eu voltei pra minha sina, contei pra uma menina, meu medo só termina estando ali, ela é suave assim, e sabe quase tudo de mim, ela sabe onde eu, queria estar enfim. É tanto, é tanto. Se ao menos você soubesse. Te quero tanto."} - Tanto (I Want You) (Bob Dylan). \end{document}