PPT Slide

What is the boiling point of a solution of 75 grams of C10 H8 in 250 grams of benzene?

D T = k m

D T = (2.53 oC/molal ) ( 0.586 moles of C10 H8 / 0.250 kg. benzene )

D T = 5.93 oC

NEW BOILING POINT = 80.1 oC + 5.93oC = 86.03 oC

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