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1

20%

2 mole/L

5 g. NaOH

1476 g.

12. 120 g. + 50 g. = 170 g. 170 g. / 170 mL = 1 g / mL

1 g / mL

13. [40 g. / (160 g. + 40 g.) ] x 100 = 20%

14. M = 85 g. NaNO3 x 1 mole / 85 g. = 1 mole

500 mL x 1 Liter / 1000 mL = 0.5 L

= 2 mole / L

15. .5m = X moles solute / .250 Kg solvent

X = .125 moles NaOH

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