If in a word of s length character, a character is repeated l times, then the number of arrangement is: 

 If there is more then one repeated character the we can write,

where, 
            l1, is the repeation times of  first repeated character.
            l2, is for second repeated character 
            and, so on�

 but remember calculating both n! and l1!* l2! * l3!* �.. *ln may occurs overflow. So I use

369 Combinations 10219 Find the ways !